## EXCEL: How to get number from any position in a string

29 May

Copy pasting as found on another website for future reference. (Link to website)

If your task implies extracting number from anywhere in a string, you can make use of the following mind-boggling formula published on MrExcel forum:

`=SUMPRODUCT(MID(0&A2, LARGE(INDEX(ISNUMBER(--MID(A2, ROW(INDIRECT("1:"&LEN(A2))), 1)) * ROW(INDIRECT("1:"&LEN(A2))), 0), ROW(INDIRECT("1:"&LEN(A2))))+1, 1) * 10^ROW(INDIRECT("1:"&LEN(A2)))/10)`

Where A2 is the original text string.

Breaking down this formula would require a separate article, so you can simply copy it to your worksheet to make sure it really works 🙂 Upon examining the results, however, you may notice one insignificant drawback – if the source string does not contain a number, the formula returns zero, as in row 6 in the screenshot above. To fix this, you can wrap the formula in the IF statement, the logical test of which checks if the source string contains any number. If it does, the formula extracts the number, otherwise returns an empty string:

`=IF(SUM(LEN(A2)-LEN(SUBSTITUTE(A2, {"0","1","2","3","4","5","6","7","8","9"}, "")))>0, SUMPRODUCT(MID(0&A2, LARGE(INDEX(ISNUMBER(--MID(A2,ROW(INDIRECT("\$1:\$"&LEN(A2))),1))* ROW(INDIRECT("\$1:\$"&LEN(A2))),0), ROW(INDIRECT("\$1:\$"&LEN(A2))))+1,1) * 10^ROW(INDIRECT("\$1:\$"&LEN(A2)))/10),"")`

As shown in the screenshot below, the improved formula works beautifully (kudos to Alex, our Excel guru, for this improvement):

Unlike in all previous examples, the result of this formula is number. To make sure of this, just notice the right-aligned values in column B and truncated leading zeros.

Credit: ablebits.com